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11331121030322 = 25665560515161
BaseRepresentation
bin1010010011100011101101…
…1100011010010010110010
31111010020121022021211221012
42210320323130122102302
52441122113440432242
640033240052230522
72246434512410552
oct244707334322262
944106538254835
1011331121030322
113679557468985
12133006960b442
1364269b94cab2
142b2601977162
15149b360ce282
hexa4e3b71a4b2

11331121030322 has 4 divisors (see below), whose sum is σ = 16996681545486. Its totient is φ = 5665560515160.

The previous prime is 11331121030301. The next prime is 11331121030367. The reversal of 11331121030322 is 22303012113311.

11331121030322 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11018954109361 + 312166920961 = 3319481^2 + 558719^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2832780257579 + ... + 2832780257582.

Almost surely, 211331121030322 is an apocalyptic number.

11331121030322 is a deficient number, since it is larger than the sum of its proper divisors (5665560515164).

11331121030322 is an equidigital number, since it uses as much as digits as its factorization.

11331121030322 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5665560515163.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 11331121030322 its reverse (22303012113311), we get a palindrome (33634133143633).

The spelling of 11331121030322 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-one million, thirty thousand, three hundred twenty-two".

Divisors: 1 2 5665560515161 11331121030322