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11331121311300 = 2235273314382609
BaseRepresentation
bin1010010011100011101101…
…1101011110111001000100
31111010020121022211010100210
42210320323131132321010
52441122114023430200
640033240102235420
72246434514661000
oct244707335367104
944106538733323
1011331121311300
11367955763aa9a
121330069725b70
1364269ba1a95b
142b2601a0b700
15149b36137650
hexa4e3b75ee44

11331121311300 has 576 divisors, whose sum is σ = 40384526336000. Its totient is φ = 2448104601600.

The previous prime is 11331121311281. The next prime is 11331121311353. The reversal of 11331121311300 is 311312113311.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 137124396 + ... + 137207004.

Almost surely, 211331121311300 is an apocalyptic number.

11331121311300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11331121311300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20192263168000).

11331121311300 is an abundant number, since it is smaller than the sum of its proper divisors (29053405024700).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11331121311300 is a wasteful number, since it uses less digits than its factorization.

11331121311300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82721 (or 82700 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 21.

Adding to 11331121311300 its reverse (311312113311), we get a palindrome (11642433424611).

The spelling of 11331121311300 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-one million, three hundred eleven thousand, three hundred".