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11331130103 = 56401200903
BaseRepresentation
bin10101000110110001…
…10101001011110111
31002020200112001100022
422203120311023313
5141201232130403
65112213235355
7550540005506
oct124330651367
932220461308
1011331130103
114895144837
122242932b5b
1310b7704917
14796c6883d
15464b9bd38
hex2a36352f7

11331130103 has 4 divisors (see below), whose sum is σ = 11331387408. Its totient is φ = 11330872800.

The previous prime is 11331130099. The next prime is 11331130117. The reversal of 11331130103 is 30103113311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11331130103 - 22 = 11331130099 is a prime.

It is a super-2 number, since 2×113311301032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11331130163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44051 + ... + 156852.

It is an arithmetic number, because the mean of its divisors is an integer number (2832846852).

Almost surely, 211331130103 is an apocalyptic number.

11331130103 is a deficient number, since it is larger than the sum of its proper divisors (257305).

11331130103 is an equidigital number, since it uses as much as digits as its factorization.

11331130103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 257304.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 11331130103 its reverse (30103113311), we get a palindrome (41434243414).

The spelling of 11331130103 in words is "eleven billion, three hundred thirty-one million, one hundred thirty thousand, one hundred three".

Divisors: 1 56401 200903 11331130103