Base | Representation |
---|---|
bin | 10101000110110001… |
… | …10101001101101111 |
3 | 1002020200112001111202 |
4 | 22203120311031233 |
5 | 141201232131343 |
6 | 5112213240115 |
7 | 550540006040 |
oct | 124330651557 |
9 | 32220461452 |
10 | 11331130223 |
11 | 4895144936 |
12 | 224293303b |
13 | 10b77049aa |
14 | 796c688c7 |
15 | 464b9bdb8 |
hex | 2a363536f |
11331130223 has 8 divisors (see below), whose sum is σ = 12951401760. Its totient is φ = 9711243360.
The previous prime is 11331130169. The next prime is 11331130253. The reversal of 11331130223 is 32203113311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11331130223 - 28 = 11331129967 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11331130195 and 11331130204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11331130253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30008 + ... + 153501.
It is an arithmetic number, because the mean of its divisors is an integer number (1618925220).
Almost surely, 211331130223 is an apocalyptic number.
11331130223 is a deficient number, since it is larger than the sum of its proper divisors (1620271537).
11331130223 is an equidigital number, since it uses as much as digits as its factorization.
11331130223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 192337.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 11331130223 its reverse (32203113311), we get a palindrome (43534243534).
The spelling of 11331130223 in words is "eleven billion, three hundred thirty-one million, one hundred thirty thousand, two hundred twenty-three".
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