1133113132131 has 4 divisors (see below), whose sum is σ = 1510817509512. Its totient is φ = 755408754752.

The previous prime is 1133113132117. The next prime is 1133113132133. The reversal of 1133113132131 is 1312313113311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1133113132131 - 2⁷ = 1133113132003 is a prime.

It is a super-2 number, since 2×1133113132131² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1133113132133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188852188686 + ... + 188852188691.

It is an arithmetic number, because the mean of its divisors is an integer number (377704377378).

Almost surely, 2^{1133113132131} is an apocalyptic number.

1133113132131 is a deficient number, since it is larger than the sum of its proper divisors (377704377381).

1133113132131 is an equidigital number, since it uses as much as digits as its factorization.

1133113132131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 377704377380.

The product of its digits is 486, while the sum is 24.

Adding to 1133113132131 its reverse (1312313113311), we get a palindrome (2445426245442).

The spelling of 1133113132131 in words is "one trillion, one hundred thirty-three billion, one hundred thirteen million, one hundred thirty-two thousand, one hundred thirty-one".