Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0110010000101101001111 |
3 | 1111010020122001221020000102 |
4 | 2210320330012100231033 |
5 | 2441122124243013403 |
6 | 40033241123321315 |
7 | 2246435004562415 |
oct | 244707406205517 |
9 | 44106561836012 |
10 | 11331132001103 |
11 | 3679562681442 |
12 | 133007122023b |
13 | 6426a0cc1495 |
14 | 2b26031d12b5 |
15 | 149b37049b88 |
hex | a4e3c190b4f |
11331132001103 has 4 divisors (see below), whose sum is σ = 11331138759360. Its totient is φ = 11331125242848.
The previous prime is 11331132001037. The next prime is 11331132001121. The reversal of 11331132001103 is 30110023113311.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 11331132001103 - 210 = 11331132000079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11331132001303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1246178 + ... + 4920896.
It is an arithmetic number, because the mean of its divisors is an integer number (2832784689840).
Almost surely, 211331132001103 is an apocalyptic number.
11331132001103 is a deficient number, since it is larger than the sum of its proper divisors (6758257).
11331132001103 is an equidigital number, since it uses as much as digits as its factorization.
11331132001103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6758256.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 11331132001103 its reverse (30110023113311), we get a palindrome (41441155114414).
The spelling of 11331132001103 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, one thousand, one hundred three".
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