Base | Representation |
---|---|
bin | 10000011111010011010… |
… | …110001110111111111111 |
3 | 11000022210020100212210210 |
4 | 100133103112032333333 |
5 | 122031113242020111 |
6 | 2224314341403503 |
7 | 144602552644464 |
oct | 20372326167777 |
9 | 4008706325723 |
10 | 1133122220031 |
11 | 3a7610a5315a |
12 | 163734409593 |
13 | 82b11c78139 |
14 | 3cbb445166b |
15 | 1e71d7620a6 |
hex | 107d358efff |
1133122220031 has 4 divisors (see below), whose sum is σ = 1510829626712. Its totient is φ = 755414813352.
The previous prime is 1133122220023. The next prime is 1133122220051. The reversal of 1133122220031 is 1300222213311.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1133122220031 - 23 = 1133122220023 is a prime.
It is a super-2 number, since 2×11331222200312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1133122220051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188853703336 + ... + 188853703341.
It is an arithmetic number, because the mean of its divisors is an integer number (377707406678).
Almost surely, 21133122220031 is an apocalyptic number.
1133122220031 is a deficient number, since it is larger than the sum of its proper divisors (377707406681).
1133122220031 is an equidigital number, since it uses as much as digits as its factorization.
1133122220031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 377707406680.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1133122220031 its reverse (1300222213311), we get a palindrome (2433344433342).
The spelling of 1133122220031 in words is "one trillion, one hundred thirty-three billion, one hundred twenty-two million, two hundred twenty thousand, thirty-one".
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