1133123303131 has 4 divisors (see below), whose sum is σ = 1134874653552. Its totient is φ = 1131371952712.

The previous prime is 1133123303119. The next prime is 1133123303161. The reversal of 1133123303131 is 1313033213311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1133123303131 is a prime.

It is a super-2 number, since 2×1133123303131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1133123303096 and 1133123303105.

It is not an unprimeable number, because it can be changed into a prime (1133123303161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 875674240 + ... + 875675533.

It is an arithmetic number, because the mean of its divisors is an integer number (283718663388).

Almost surely, 2^{1133123303131} is an apocalyptic number.

1133123303131 is a deficient number, since it is larger than the sum of its proper divisors (1751350421).

1133123303131 is an equidigital number, since it uses as much as digits as its factorization.

1133123303131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1751350420.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 1133123303131 its reverse (1313033213311), we get a palindrome (2446156516442).

The spelling of 1133123303131 in words is "one trillion, one hundred thirty-three billion, one hundred twenty-three million, three hundred three thousand, one hundred thirty-one".