1133130114403 has 4 divisors (see below), whose sum is σ = 1295005845040. Its totient is φ = 971254383768.

The previous prime is 1133130114397. The next prime is 1133130114419. The reversal of 1133130114403 is 3044110313311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1133130114403 - 2²¹ = 1133128017251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1133130114503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80937865308 + ... + 80937865321.

It is an arithmetic number, because the mean of its divisors is an integer number (323751461260).

Almost surely, 2^{1133130114403} is an apocalyptic number.

1133130114403 is a deficient number, since it is larger than the sum of its proper divisors (161875730637).

1133130114403 is an equidigital number, since it uses as much as digits as its factorization.

1133130114403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 161875730636.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1133130114403 its reverse (3044110313311), we get a palindrome (4177240427714).

The spelling of 1133130114403 in words is "one trillion, one hundred thirty-three billion, one hundred thirty million, one hundred fourteen thousand, four hundred three".