Base | Representation |
---|---|
bin | 110100110000111111… |
… | …1001011000101000111 |
3 | 101211110222120220022022 |
4 | 1221201333023011013 |
5 | 3324031123200403 |
6 | 124015540553355 |
7 | 11121001313300 |
oct | 1514177130507 |
9 | 354428526268 |
10 | 113313100103 |
11 | 44068322275 |
12 | 19b643b285b |
13 | a8baa17b78 |
14 | 56ad20d7a7 |
15 | 2e32dd6d38 |
hex | 1a61fcb147 |
113313100103 has 12 divisors (see below), whose sum is σ = 135375719112. Its totient is φ = 94500498960.
The previous prime is 113313100093. The next prime is 113313100123. The reversal of 113313100103 is 301001313311.
It is not a de Polignac number, because 113313100103 - 212 = 113313096007 is a prime.
It is a super-2 number, since 2×1133131001032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113313100123) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 31248353 + ... + 31251978.
It is an arithmetic number, because the mean of its divisors is an integer number (11281309926).
Almost surely, 2113313100103 is an apocalyptic number.
113313100103 is a deficient number, since it is larger than the sum of its proper divisors (22062619009).
113313100103 is an equidigital number, since it uses as much as digits as its factorization.
113313100103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62500382 (or 62500375 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 113313100103 its reverse (301001313311), we get a palindrome (414314413414).
The spelling of 113313100103 in words is "one hundred thirteen billion, three hundred thirteen million, one hundred thousand, one hundred three".
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