Search a number
-
+
113313100103 = 723762500331
BaseRepresentation
bin110100110000111111…
…1001011000101000111
3101211110222120220022022
41221201333023011013
53324031123200403
6124015540553355
711121001313300
oct1514177130507
9354428526268
10113313100103
1144068322275
1219b643b285b
13a8baa17b78
1456ad20d7a7
152e32dd6d38
hex1a61fcb147

113313100103 has 12 divisors (see below), whose sum is σ = 135375719112. Its totient is φ = 94500498960.

The previous prime is 113313100093. The next prime is 113313100123. The reversal of 113313100103 is 301001313311.

It is not a de Polignac number, because 113313100103 - 212 = 113313096007 is a prime.

It is a super-2 number, since 2×1133131001032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113313100123) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 31248353 + ... + 31251978.

It is an arithmetic number, because the mean of its divisors is an integer number (11281309926).

Almost surely, 2113313100103 is an apocalyptic number.

113313100103 is a deficient number, since it is larger than the sum of its proper divisors (22062619009).

113313100103 is an equidigital number, since it uses as much as digits as its factorization.

113313100103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62500382 (or 62500375 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 113313100103 its reverse (301001313311), we get a palindrome (414314413414).

The spelling of 113313100103 in words is "one hundred thirteen billion, three hundred thirteen million, one hundred thousand, one hundred three".

Divisors: 1 7 37 49 259 1813 62500331 437502317 2312512247 3062516219 16187585729 113313100103