Base | Representation |
---|---|
bin | 10000011111010011111… |
… | …000001001111011000011 |
3 | 11000022210212002122110211 |
4 | 100133103320021323003 |
5 | 122031123031042011 |
6 | 2224315300134551 |
7 | 144603021351124 |
oct | 20372370117303 |
9 | 4008725078424 |
10 | 1133131112131 |
11 | 3a7615a769a7 |
12 | 163737397457 |
13 | 82b13a6c635 |
14 | 3cbb56c804b |
15 | 1e71e41bb21 |
hex | 107d3e09ec3 |
1133131112131 has 4 divisors (see below), whose sum is σ = 1151707032064. Its totient is φ = 1114555192200.
The previous prime is 1133131112129. The next prime is 1133131112137. The reversal of 1133131112131 is 1312111313311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1133131112131 - 21 = 1133131112129 is a prime.
It is a super-2 number, since 2×11331311121312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1133131112137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9287959875 + ... + 9287959996.
It is an arithmetic number, because the mean of its divisors is an integer number (287926758016).
Almost surely, 21133131112131 is an apocalyptic number.
1133131112131 is a deficient number, since it is larger than the sum of its proper divisors (18575919933).
1133131112131 is an equidigital number, since it uses as much as digits as its factorization.
1133131112131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18575919932.
The product of its digits is 162, while the sum is 22.
Adding to 1133131112131 its reverse (1312111313311), we get a palindrome (2445242425442).
The spelling of 1133131112131 in words is "one trillion, one hundred thirty-three billion, one hundred thirty-one million, one hundred twelve thousand, one hundred thirty-one".
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