1133131112130 has 32 divisors (see below), whose sum is σ = 2765608142400. Its totient is φ = 297046799552.

The previous prime is 1133131112129. The next prime is 1133131112137. The reversal of 1133131112130 is 312111313311.

It is a super-2 number, since 2×1133131112130² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1133131112097 and 1133131112106.

It is not an unprimeable number, because it can be changed into a prime (1133131112137) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 320091765 + ... + 320095304.

It is an arithmetic number, because the mean of its divisors is an integer number (86425254450).

Almost surely, 2^{1133131112130} is an apocalyptic number.

1133131112130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1133131112130 is an abundant number, since it is smaller than the sum of its proper divisors (1632477030270).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1133131112130 is a wasteful number, since it uses less digits than its factorization.

1133131112130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 640187138.

The product of its (nonzero) digits is 162, while the sum is 21.

Adding to 1133131112130 its reverse (312111313311), we get a palindrome (1445242425441).

The spelling of 1133131112130 in words is "one trillion, one hundred thirty-three billion, one hundred thirty-one million, one hundred twelve thousand, one hundred thirty".