Base | Representation |
---|---|
bin | 1010010011100100011011… |
… | …0101011010010011010101 |
3 | 1111010021002121212212222111 |
4 | 2210321012311122103111 |
5 | 2441123011401231313 |
6 | 40033311040231021 |
7 | 2246442322641313 |
oct | 244710665322325 |
9 | 44107077785874 |
10 | 11331312133333 |
11 | 3679645324455 |
12 | 133010160b471 |
13 | 6426cc4105ba |
14 | 2b261d0c10b3 |
15 | 149b47c7c43d |
hex | a4e46d5a4d5 |
11331312133333 has 4 divisors (see below), whose sum is σ = 11997859905900. Its totient is φ = 10664764360768.
The previous prime is 11331312133307. The next prime is 11331312133357. The reversal of 11331312133333 is 33333121313311.
11331312133333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 9504038111044 + 1827274022289 = 3082862^2 + 1351767^2 .
It is a cyclic number.
It is not a de Polignac number, because 11331312133333 - 25 = 11331312133301 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11331312133295 and 11331312133304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11331312133433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333273886258 + ... + 333273886291.
It is an arithmetic number, because the mean of its divisors is an integer number (2999464976475).
Almost surely, 211331312133333 is an apocalyptic number.
It is an amenable number.
11331312133333 is a deficient number, since it is larger than the sum of its proper divisors (666547772567).
11331312133333 is an equidigital number, since it uses as much as digits as its factorization.
11331312133333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 666547772566.
The product of its digits is 13122, while the sum is 31.
Adding to 11331312133333 its reverse (33333121313311), we get a palindrome (44664433446644).
The spelling of 11331312133333 in words is "eleven trillion, three hundred thirty-one billion, three hundred twelve million, one hundred thirty-three thousand, three hundred thirty-three".
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