Base | Representation |
---|---|
bin | 1010010011100111000010… |
… | …0011001100010001000011 |
3 | 1111010022220101210211000010 |
4 | 2210321300203030101003 |
5 | 2441130430033002243 |
6 | 40033504321000003 |
7 | 2246465551500000 |
oct | 244716043142103 |
9 | 44108811724003 |
10 | 11332012000323 |
11 | 3679974392923 |
12 | 1330277a83003 |
13 | 6427b1404291 |
14 | 2b26880228a7 |
15 | 149b89425433 |
hex | a4e708cc443 |
11332012000323 has 48 divisors (see below), whose sum is σ = 17789152508160. Its totient is φ = 6416024652576.
The previous prime is 11332012000301. The next prime is 11332012000327. The reversal of 11332012000323 is 32300021023311.
It is not a de Polignac number, because 11332012000323 - 29 = 11332011999811 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 11332012000323.
It is not an unprimeable number, because it can be changed into a prime (11332012000327) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4464936 + ... + 6526842.
It is an arithmetic number, because the mean of its divisors is an integer number (370607343920).
Almost surely, 211332012000323 is an apocalyptic number.
11332012000323 is a deficient number, since it is larger than the sum of its proper divisors (6457140507837).
11332012000323 is an frugal number, since it uses more digits than its factorization.
11332012000323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2062054 (or 2062026 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 11332012000323 its reverse (32300021023311), we get a palindrome (43632033023634).
The spelling of 11332012000323 in words is "eleven trillion, three hundred thirty-two billion, twelve million, three hundred twenty-three", and thus it is an aban number.
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