11332033121333 has 4 divisors (see below), whose sum is σ = 11401554797088. Its totient is φ = 11262511445580.

The previous prime is 11332033121323. The next prime is 11332033121347. The reversal of 11332033121333 is 33312133023311.

11332033121333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11332033121333 - 2⁸ = 11332033121077 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11332033121296 and 11332033121305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11332033121323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34760837633 + ... + 34760837958.

It is an arithmetic number, because the mean of its divisors is an integer number (2850388699272).

Almost surely, 2^{11332033121333} is an apocalyptic number.

It is an amenable number.

11332033121333 is a deficient number, since it is larger than the sum of its proper divisors (69521675755).

11332033121333 is an equidigital number, since it uses as much as digits as its factorization.

11332033121333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69521675754.

The product of its (nonzero) digits is 8748, while the sum is 29.

Adding to 11332033121333 its reverse (33312133023311), we get a palindrome (44644166144644).

The spelling of 11332033121333 in words is "eleven trillion, three hundred thirty-two billion, thirty-three million, one hundred twenty-one thousand, three hundred thirty-three".