Base | Representation |
---|---|
bin | 1010010011100111001001… |
… | …1101010011011101001101 |
3 | 1111010022222122001010212101 |
4 | 2210321302131103131031 |
5 | 2441131011231330331 |
6 | 40033511423035101 |
7 | 2246466420542404 |
oct | 244716235233515 |
9 | 44108878033771 |
10 | 11332044011341 |
11 | 3679990467209 |
12 | 133028673ba91 |
13 | 6427b7c31701 |
14 | 2b268c39663b |
15 | 149b8c14a061 |
hex | a4e7275374d |
11332044011341 has 8 divisors (see below), whose sum is σ = 11354163125760. Its totient is φ = 11309926622112.
The previous prime is 11332044011287. The next prime is 11332044011357. The reversal of 11332044011341 is 14311044023311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11332044011341 - 213 = 11332044003149 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11332044011371) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13134420 + ... + 13970578.
It is an arithmetic number, because the mean of its divisors is an integer number (1419270390720).
Almost surely, 211332044011341 is an apocalyptic number.
It is an amenable number.
11332044011341 is a deficient number, since it is larger than the sum of its proper divisors (22119114419).
11332044011341 is an equidigital number, since it uses as much as digits as its factorization.
11332044011341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 862595.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 11332044011341 its reverse (14311044023311), we get a palindrome (25643088034652).
The spelling of 11332044011341 in words is "eleven trillion, three hundred thirty-two billion, forty-four million, eleven thousand, three hundred forty-one".
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