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1133242041055 = 51789126689999
BaseRepresentation
bin10000011111011010011…
…111010100001011011111
311000100002120211102100111
4100133122133110023133
5122031334430303210
62224334301510451
7144605536262065
oct20373237241337
94010076742314
101133242041055
113a76726524a3
12163768572427
1382b30a3b757
143cbc6322035
151e72902e88a
hex107da7d42df

1133242041055 has 8 divisors (see below), whose sum is σ = 1360650600000. Its totient is φ = 906086865696.

The previous prime is 1133242041023. The next prime is 1133242041067. The reversal of 1133242041055 is 5501402423311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1133242041055 - 25 = 1133242041023 is a prime.

It is a super-2 number, since 2×11332420410552 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 63336055 + ... + 63353944.

It is an arithmetic number, because the mean of its divisors is an integer number (170081325000).

Almost surely, 21133242041055 is an apocalyptic number.

1133242041055 is a deficient number, since it is larger than the sum of its proper divisors (227408558945).

1133242041055 is a wasteful number, since it uses less digits than its factorization.

1133242041055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 126691793.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1133242041055 its reverse (5501402423311), we get a palindrome (6634644464366).

The spelling of 1133242041055 in words is "one trillion, one hundred thirty-three billion, two hundred forty-two million, forty-one thousand, fifty-five".

Divisors: 1 5 1789 8945 126689999 633449995 226648408211 1133242041055