Base | Representation |
---|---|
bin | 11001110001001100110000… |
… | …111100001011010110000111 |
3 | 112212021110000112001201012200 |
4 | 121301030300330023112013 |
5 | 104323313142004333111 |
6 | 1041012020354245543 |
7 | 32604655442650353 |
oct | 3161146074132607 |
9 | 485243015051180 |
10 | 113332123121031 |
11 | 33124979a37481 |
12 | 108646368868b3 |
13 | 4b31233b19a89 |
14 | 1ddb43836c463 |
15 | d18066822256 |
hex | 671330f0b587 |
113332123121031 has 12 divisors (see below), whose sum is σ = 163892973081552. Its totient is φ = 75466586841696.
The previous prime is 113332123121003. The next prime is 113332123121071. The reversal of 113332123121031 is 130121321233311.
113332123121031 is a `hidden beast` number, since 1 + 1 + 3 + 3 + 321 + 231 + 2 + 103 + 1 = 666.
It is not a de Polignac number, because 113332123121031 - 213 = 113332123112839 is a prime.
It is a super-2 number, since 2×1133321231210312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113332123120986 and 113332123121004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113332123121071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7346817331 + ... + 7346832756.
It is an arithmetic number, because the mean of its divisors is an integer number (13657747756796).
Almost surely, 2113332123121031 is an apocalyptic number.
113332123121031 is a deficient number, since it is larger than the sum of its proper divisors (50560849960521).
113332123121031 is a wasteful number, since it uses less digits than its factorization.
113332123121031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14693650950 (or 14693650947 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 27.
Adding to 113332123121031 its reverse (130121321233311), we get a palindrome (243453444354342).
The spelling of 113332123121031 in words is "one hundred thirteen trillion, three hundred thirty-two billion, one hundred twenty-three million, one hundred twenty-one thousand, thirty-one".
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