1133322012033 has 4 divisors (see below), whose sum is σ = 1511096016048. Its totient is φ = 755548008020.

The previous prime is 1133322011971. The next prime is 1133322012041. The reversal of 1133322012033 is 3302102233311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1133322012033 - 2¹⁰ = 1133322011009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1133322011994 and 1133322012012.

It is not an unprimeable number, because it can be changed into a prime (1133322022033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188887002003 + ... + 188887002008.

It is an arithmetic number, because the mean of its divisors is an integer number (377774004012).

Almost surely, 2^{1133322012033} is an apocalyptic number.

It is an amenable number.

1133322012033 is a deficient number, since it is larger than the sum of its proper divisors (377774004015).

1133322012033 is an equidigital number, since it uses as much as digits as its factorization.

1133322012033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 377774004014.

The product of its (nonzero) digits is 1944, while the sum is 24.

Adding to 1133322012033 its reverse (3302102233311), we get a palindrome (4435424245344).

The spelling of 1133322012033 in words is "one trillion, one hundred thirty-three billion, three hundred twenty-two million, twelve thousand, thirty-three".