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11334403123330 = 2571724373178489
BaseRepresentation
bin1010010011101111111100…
…0100100110100010000010
31111010120002001010110010111
42210323333010212202002
52441200324144421310
640034541455021534
72246612034632050
oct244737704464202
944116061113114
1011334403123330
11367a991091a41
12133082480a8aa
13642aa2902571
142b28338111d0
15149c792e628a
hexa4eff126882

11334403123330 has 192 divisors, whose sum is σ = 25692073355520. Its totient is φ = 3523473063936.

The previous prime is 11334403123321. The next prime is 11334403123391. The reversal of 11334403123330 is 3332130443311.

It is a junction number, because it is equal to n+sod(n) for n = 11334403123292 and 11334403123301.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 63412726 + ... + 63591214.

It is an arithmetic number, because the mean of its divisors is an integer number (133812882060).

Almost surely, 211334403123330 is an apocalyptic number.

11334403123330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11334403123330 is an abundant number, since it is smaller than the sum of its proper divisors (14357670232190).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11334403123330 is a wasteful number, since it uses less digits than its factorization.

11334403123330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 178653 (or 178636 counting only the distinct ones).

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 11334403123330 its reverse (3332130443311), we get a palindrome (14666533566641).

The spelling of 11334403123330 in words is "eleven trillion, three hundred thirty-four billion, four hundred three million, one hundred twenty-three thousand, three hundred thirty".