1133440440331 has 4 divisors (see below), whose sum is σ = 1134593483472. Its totient is φ = 1132287397192.

The previous prime is 1133440440283. The next prime is 1133440440367. The reversal of 1133440440331 is 1330440443311.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1133440440331 - 2¹⁷ = 1133440309259 is a prime.

It is a super-2 number, since 2×1133440440331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1133440440293 and 1133440440302.

It is not an unprimeable number, because it can be changed into a prime (1133440440371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 576520096 + ... + 576522061.

It is an arithmetic number, because the mean of its divisors is an integer number (283648370868).

Almost surely, 2^{1133440440331} is an apocalyptic number.

1133440440331 is a deficient number, since it is larger than the sum of its proper divisors (1153043141).

1133440440331 is an equidigital number, since it uses as much as digits as its factorization.

1133440440331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1153043140.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1133440440331 its reverse (1330440443311), we get a palindrome (2463880883642).

The spelling of 1133440440331 in words is "one trillion, one hundred thirty-three billion, four hundred forty million, four hundred forty thousand, three hundred thirty-one".