Base | Representation |
---|---|
bin | 10000011111100110011… |
… | …010000110010110111001 |
3 | 11000100121112002101212221 |
4 | 100133212122012112321 |
5 | 122032242123002223 |
6 | 2224410203404041 |
7 | 144613515016510 |
oct | 20374632062671 |
9 | 4010545071787 |
10 | 1133442000313 |
11 | 3a7765507887 |
12 | 163803523621 |
13 | 82b632b033c |
14 | 3cc04ad3677 |
15 | 1e73b87bb5d |
hex | 107e66865b9 |
1133442000313 has 4 divisors (see below), whose sum is σ = 1295362286080. Its totient is φ = 971521714548.
The previous prime is 1133442000281. The next prime is 1133442000329. The reversal of 1133442000313 is 3130002443311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1133442000313 - 25 = 1133442000281 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1133442000343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80960142873 + ... + 80960142886.
It is an arithmetic number, because the mean of its divisors is an integer number (323840571520).
Almost surely, 21133442000313 is an apocalyptic number.
It is an amenable number.
1133442000313 is a deficient number, since it is larger than the sum of its proper divisors (161920285767).
1133442000313 is an equidigital number, since it uses as much as digits as its factorization.
1133442000313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 161920285766.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1133442000313 its reverse (3130002443311), we get a palindrome (4263444443624).
The spelling of 1133442000313 in words is "one trillion, one hundred thirty-three billion, four hundred forty-two million, three hundred thirteen", and thus it is an aban number.
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