Base | Representation |
---|---|
bin | 110100110010000110… |
… | …1011101110100011111 |
3 | 101211120120202222221112 |
4 | 1221210031131310133 |
5 | 3324120200320221 |
6 | 124023352252235 |
7 | 11121633341210 |
oct | 1514415356437 |
9 | 354516688845 |
10 | 113350401311 |
11 | 4408738a214 |
12 | 19b749a107b |
13 | a8c56781a4 |
14 | 56b415d407 |
15 | 2e3630415b |
hex | 1a6435dd1f |
113350401311 has 4 divisors (see below), whose sum is σ = 129543315792. Its totient is φ = 97157486832.
The previous prime is 113350401293. The next prime is 113350401313. The reversal of 113350401311 is 113104053311.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-113350401311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113350401313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8096457230 + ... + 8096457243.
It is an arithmetic number, because the mean of its divisors is an integer number (32385828948).
Almost surely, 2113350401311 is an apocalyptic number.
113350401311 is a deficient number, since it is larger than the sum of its proper divisors (16192914481).
113350401311 is an equidigital number, since it uses as much as digits as its factorization.
113350401311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16192914480.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 113350401311 its reverse (113104053311), we get a palindrome (226454454622).
The spelling of 113350401311 in words is "one hundred thirteen billion, three hundred fifty million, four hundred one thousand, three hundred eleven".
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