11335122135 has 12 divisors (see below), whose sum is σ = 19647545112. Its totient is φ = 6045398448.

The previous prime is 11335122133. The next prime is 11335122143. The reversal of 11335122135 is 53122153311.

11335122135 is a `hidden beast` number, since 1 + 13 + 3 + 512 + 2 + 135 = 666.

11335122135 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11335122135 - 2¹ = 11335122133 is a prime.

It is a super-3 number, since 3×11335122135³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11335122099 and 11335122108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11335122133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 125945757 + ... + 125945846.

It is an arithmetic number, because the mean of its divisors is an integer number (1637295426).

Almost surely, 2^11335122135 is an apocalyptic number.

11335122135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

11335122135 is a deficient number, since it is larger than the sum of its proper divisors (8312422977).

11335122135 is a wasteful number, since it uses less digits than its factorization.

11335122135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 251891614 (or 251891611 counting only the distinct ones).

The product of its digits is 2700, while the sum is 27.

Adding to 11335122135 its reverse (53122153311), we get a palindrome (64457275446).

The spelling of 11335122135 in words is "eleven billion, three hundred thirty-five million, one hundred twenty-two thousand, one hundred thirty-five".