113351643403 has 4 divisors (see below), whose sum is σ = 113540878800. Its totient is φ = 113162408008.

The previous prime is 113351643401. The next prime is 113351643421. The reversal of 113351643403 is 304346153311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304346153311 = 107 ⋅2844356573.

It is a cyclic number.

It is not a de Polignac number, because 113351643403 - 2¹ = 113351643401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113351643401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94616800 + ... + 94617997.

It is an arithmetic number, because the mean of its divisors is an integer number (28385219700).

Almost surely, 2^113351643403 is an apocalyptic number.

113351643403 is a deficient number, since it is larger than the sum of its proper divisors (189235397).

113351643403 is an equidigital number, since it uses as much as digits as its factorization.

113351643403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 189235396.

The product of its (nonzero) digits is 38880, while the sum is 34.

Adding to 113351643403 its reverse (304346153311), we get a palindrome (417697796714).

The spelling of 113351643403 in words is "one hundred thirteen billion, three hundred fifty-one million, six hundred forty-three thousand, four hundred three".