11335304121 has 4 divisors (see below), whose sum is σ = 15113738832. Its totient is φ = 7556869412.

The previous prime is 11335304117. The next prime is 11335304129. The reversal of 11335304121 is 12140353311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11335304121 - 2² = 11335304117 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11335304091 and 11335304100.

It is not an unprimeable number, because it can be changed into a prime (11335304129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1889217351 + ... + 1889217356.

It is an arithmetic number, because the mean of its divisors is an integer number (3778434708).

Almost surely, 2^11335304121 is an apocalyptic number.

It is an amenable number.

11335304121 is a deficient number, since it is larger than the sum of its proper divisors (3778434711).

11335304121 is an equidigital number, since it uses as much as digits as its factorization.

11335304121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3778434710.

The product of its (nonzero) digits is 1080, while the sum is 24.

Adding to 11335304121 its reverse (12140353311), we get a palindrome (23475657432).

The spelling of 11335304121 in words is "eleven billion, three hundred thirty-five million, three hundred four thousand, one hundred twenty-one".