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113354130525141 = 3115875851743871
BaseRepresentation
bin11001110001100001010000…
…101011110000101111010101
3112212100112211020212200012210
4121301201100223300233111
5104324143224403301031
61041030100233304033
732606365011544362
oct3161412053605725
9485315736780183
10113354130525141
11331332425aa960
1210868958b65019
134b33330361b9c
141ddc5250b9469
15d18903914746
hex671850af0bd5

113354130525141 has 16 divisors (see below), whose sum is σ = 165159619043328. Its totient is φ = 68582438156400.

The previous prime is 113354130525109. The next prime is 113354130525187. The reversal of 113354130525141 is 141525031453311.

It is not a de Polignac number, because 113354130525141 - 25 = 113354130525109 is a prime.

It is a super-2 number, since 2×1133541305251412 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 113354130525141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113354130525101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2925852565 + ... + 2925891306.

It is an arithmetic number, because the mean of its divisors is an integer number (10322476190208).

Almost surely, 2113354130525141 is an apocalyptic number.

113354130525141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

113354130525141 is a deficient number, since it is larger than the sum of its proper divisors (51805488518187).

113354130525141 is a wasteful number, since it uses less digits than its factorization.

113354130525141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5851744472.

The product of its (nonzero) digits is 108000, while the sum is 39.

Adding to 113354130525141 its reverse (141525031453311), we get a palindrome (254879161978452).

The spelling of 113354130525141 in words is "one hundred thirteen trillion, three hundred fifty-four billion, one hundred thirty million, five hundred twenty-five thousand, one hundred forty-one".

Divisors: 1 3 11 33 587 1761 6457 19371 5851743871 17555231613 64369182581 193107547743 3434973652277 10304920956831 37784710175047 113354130525141