113365529907840 has 512 divisors, whose sum is σ = 458986604544000. Its totient is φ = 25904998748160.

The previous prime is 113365529907829. The next prime is 113365529907869. The reversal of 113365529907840 is 48709925563311.

113365529907840 is a `hidden beast` number, since 1 + 1 + 3 + 3 + 6 + 552 + 9 + 9 + 0 + 78 + 4 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (63).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 446336401 + ... + 446590319.

It is an arithmetic number, because the mean of its divisors is an integer number (896458212000).

It is a 1-persistent number, because it is pandigital, but 2⋅113365529907840 = 226731059815680 is not.

Almost surely, 2^{113365529907840} is an apocalyptic number.

113365529907840 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113365529907840, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (229493302272000).

113365529907840 is an abundant number, since it is smaller than the sum of its proper divisors (345621074636160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113365529907840 is a wasteful number, since it uses less digits than its factorization.

113365529907840 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 257645 (or 257627 counting only the distinct ones).

The product of its (nonzero) digits is 48988800, while the sum is 63.

The spelling of 113365529907840 in words is "one hundred thirteen trillion, three hundred sixty-five billion, five hundred twenty-nine million, nine hundred seven thousand, eight hundred forty".