113400041401 has 4 divisors (see below), whose sum is σ = 114265690704. Its totient is φ = 112534392100.

The previous prime is 113400041399. The next prime is 113400041411. The reversal of 113400041401 is 104140004311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 104140004311 = 7 ⋅14877143473.

It is a cyclic number.

It is not a de Polignac number, because 113400041401 - 2¹ = 113400041399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113400041411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 432824455 + ... + 432824716.

It is an arithmetic number, because the mean of its divisors is an integer number (28566422676).

Almost surely, 2^113400041401 is an apocalyptic number.

It is an amenable number.

113400041401 is a deficient number, since it is larger than the sum of its proper divisors (865649303).

113400041401 is an equidigital number, since it uses as much as digits as its factorization.

113400041401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 865649302.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 113400041401 its reverse (104140004311), we get a palindrome (217540045712).

The spelling of 113400041401 in words is "one hundred thirteen billion, four hundred million, forty-one thousand, four hundred one".