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1134101211143 = 1813036255281
BaseRepresentation
bin10000100000001101101…
…100110010100000000111
311000102022110111210010212
4100200031230302200013
5122040114402224033
62224555432510035
7144636041145125
oct20401554624007
94012273453125
101134101211143
113a7a7362771a
1216396824b31b
1382c39a3a914
143cc68490915
151e779693748
hex1080db32807

1134101211143 has 4 divisors (see below), whose sum is σ = 1134107647728. Its totient is φ = 1134094774560.

The previous prime is 1134101211119. The next prime is 1134101211161. The reversal of 1134101211143 is 3411121014311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1134101211143 - 236 = 1065381734407 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1134101211343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2946338 + ... + 3308943.

It is an arithmetic number, because the mean of its divisors is an integer number (283526911932).

Almost surely, 21134101211143 is an apocalyptic number.

1134101211143 is a deficient number, since it is larger than the sum of its proper divisors (6436585).

1134101211143 is an equidigital number, since it uses as much as digits as its factorization.

1134101211143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6436584.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 1134101211143 its reverse (3411121014311), we get a palindrome (4545222225454).

The spelling of 1134101211143 in words is "one trillion, one hundred thirty-four billion, one hundred one million, two hundred eleven thousand, one hundred forty-three".

Divisors: 1 181303 6255281 1134101211143