Base | Representation |
---|---|
bin | 10000100000001110001… |
… | …111001000100011001111 |
3 | 11000102100002110012020000 |
4 | 100200032033020203033 |
5 | 122040124203324401 |
6 | 2225000353455343 |
7 | 144636210523422 |
oct | 20401617104317 |
9 | 4012302405200 |
10 | 1134110214351 |
11 | 3a7a78716994 |
12 | 16396b271553 |
13 | 82c3b87086a |
14 | 3cc697559b9 |
15 | 1e77a371186 |
hex | 1080e3c88cf |
1134110214351 has 20 divisors (see below), whose sum is σ = 1695308753424. Its totient is φ = 755562880800.
The previous prime is 1134110214329. The next prime is 1134110214403. The reversal of 1134110214351 is 1534120114311.
1134110214351 is a `hidden beast` number, since 1 + 1 + 3 + 411 + 0 + 214 + 35 + 1 = 666.
It is not a de Polignac number, because 1134110214351 - 221 = 1134108117199 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1134110214551) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 4607035 + ... + 4846956.
Almost surely, 21134110214351 is an apocalyptic number.
1134110214351 is a deficient number, since it is larger than the sum of its proper divisors (561198539073).
1134110214351 is an equidigital number, since it uses as much as digits as its factorization.
1134110214351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9455484 (or 9455475 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 27.
Adding to 1134110214351 its reverse (1534120114311), we get a palindrome (2668230328662).
The spelling of 1134110214351 in words is "one trillion, one hundred thirty-four billion, one hundred ten million, two hundred fourteen thousand, three hundred fifty-one".
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