113411330433 has 24 divisors (see below), whose sum is σ = 164290421568. Its totient is φ = 75389082912.

The previous prime is 113411330411. The next prime is 113411330489. The reversal of 113411330433 is 334033114311.

113411330433 is a `hidden beast` number, since 1 + 1 + 341 + 13 + 304 + 3 + 3 = 666.

It is not a de Polignac number, because 113411330433 - 2¹² = 113411326337 is a prime.

It is a super-2 number, since 2×113411330433² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113411330397 and 113411330406.

It is not an unprimeable number, because it can be changed into a prime (113411331433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4416810 + ... + 4442412.

It is an arithmetic number, because the mean of its divisors is an integer number (6845434232).

Almost surely, 2^113411330433 is an apocalyptic number.

It is an amenable number.

113411330433 is a deficient number, since it is larger than the sum of its proper divisors (50879091135).

113411330433 is a wasteful number, since it uses less digits than its factorization.

113411330433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27013 (or 27010 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 27.

Adding to 113411330433 its reverse (334033114311), we get a palindrome (447444444744).

The spelling of 113411330433 in words is "one hundred thirteen billion, four hundred eleven million, three hundred thirty thousand, four hundred thirty-three".