Base | Representation |
---|---|
bin | 1010010100001001000000… |
… | …1110110001010011110111 |
3 | 1111011012110002102121010112 |
4 | 2211002100032301103313 |
5 | 2441303120130440120 |
6 | 40042013401213235 |
7 | 2250240600531065 |
oct | 245022016612367 |
9 | 44135402377115 |
10 | 11341133452535 |
11 | 3682825197987 |
12 | 1331ba279121b |
13 | 643606099493 |
14 | 2b2cb1611035 |
15 | 14a0200e2bc5 |
hex | a50903b14f7 |
11341133452535 has 8 divisors (see below), whose sum is σ = 13679874963600. Its totient is φ = 9025896881664.
The previous prime is 11341133452501. The next prime is 11341133452589. The reversal of 11341133452535 is 53525433114311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11341133452535 - 222 = 11341129258231 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11341133452492 and 11341133452501.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5876233985 + ... + 5876235914.
It is an arithmetic number, because the mean of its divisors is an integer number (1709984370450).
Almost surely, 211341133452535 is an apocalyptic number.
11341133452535 is a deficient number, since it is larger than the sum of its proper divisors (2338741511065).
11341133452535 is a wasteful number, since it uses less digits than its factorization.
11341133452535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11752470097.
The product of its digits is 324000, while the sum is 41.
Adding to 11341133452535 its reverse (53525433114311), we get a palindrome (64866566566846).
The spelling of 11341133452535 in words is "eleven trillion, three hundred forty-one billion, one hundred thirty-three million, four hundred fifty-two thousand, five hundred thirty-five".
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