Base | Representation |
---|---|
bin | 11001110010010110100110… |
… | …111000010100110100110101 |
3 | 112212120000200020122011221001 |
4 | 121302112212320110310311 |
5 | 104331113032233442401 |
6 | 1041112252201523301 |
7 | 32613463331542021 |
oct | 3162264670246465 |
9 | 485500606564831 |
10 | 113411411234101 |
11 | 33155567015352 |
12 | 10877a841a3531 |
13 | 4b3885b60cb06 |
14 | 20011da757381 |
15 | d1a157571601 |
hex | 6725a6e14d35 |
113411411234101 has 4 divisors (see below), whose sum is σ = 114512492896672. Its totient is φ = 112310329571532.
The previous prime is 113411411234063. The next prime is 113411411234131. The reversal of 113411411234101 is 101432114114311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 113411411234101 - 235 = 113377051495733 is a prime.
It is a super-2 number, since 2×1134114112341012 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 113411411234101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113411411234131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 550540831131 + ... + 550540831336.
It is an arithmetic number, because the mean of its divisors is an integer number (28628123224168).
Almost surely, 2113411411234101 is an apocalyptic number.
It is an amenable number.
113411411234101 is a deficient number, since it is larger than the sum of its proper divisors (1101081662571).
113411411234101 is a wasteful number, since it uses less digits than its factorization.
113411411234101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1101081662570.
The product of its (nonzero) digits is 1152, while the sum is 28.
Adding to 113411411234101 its reverse (101432114114311), we get a palindrome (214843525348412).
The spelling of 113411411234101 in words is "one hundred thirteen trillion, four hundred eleven billion, four hundred eleven million, two hundred thirty-four thousand, one hundred one".
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