Base | Representation |
---|---|
bin | 10101000111111110… |
… | …10011001001111101 |
3 | 1002021101111101022022 |
4 | 22203333103021331 |
5 | 141211322324313 |
6 | 5113213325525 |
7 | 551021505551 |
oct | 124377231175 |
9 | 32241441268 |
10 | 11341214333 |
11 | 489a902209 |
12 | 22461968a5 |
13 | 10b9825917 |
14 | 798331861 |
15 | 4659dec08 |
hex | 2a3fd327d |
11341214333 has 4 divisors (see below), whose sum is σ = 11341454748. Its totient is φ = 11340973920.
The previous prime is 11341214329. The next prime is 11341214347. The reversal of 11341214333 is 33341214311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5287907524 + 6053306809 = 72718^2 + 77803^2 .
It is a cyclic number.
It is not a de Polignac number, because 11341214333 - 22 = 11341214329 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11341214393) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23528 + ... + 152433.
It is an arithmetic number, because the mean of its divisors is an integer number (2835363687).
Almost surely, 211341214333 is an apocalyptic number.
It is an amenable number.
11341214333 is a deficient number, since it is larger than the sum of its proper divisors (240415).
11341214333 is an equidigital number, since it uses as much as digits as its factorization.
11341214333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 240414.
The product of its digits is 2592, while the sum is 26.
Adding to 11341214333 its reverse (33341214311), we get a palindrome (44682428644).
The spelling of 11341214333 in words is "eleven billion, three hundred forty-one million, two hundred fourteen thousand, three hundred thirty-three".
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