113413135333 has 4 divisors (see below), whose sum is σ = 113887667520. Its totient is φ = 112938603148.

The previous prime is 113413135327. The next prime is 113413135369. The reversal of 113413135333 is 333531314311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113413135333 is a prime.

It is a super-2 number, since 2×113413135333² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113413135295 and 113413135304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113413135393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 237265735 + ... + 237266212.

It is an arithmetic number, because the mean of its divisors is an integer number (28471916880).

Almost surely, 2^113413135333 is an apocalyptic number.

It is an amenable number.

113413135333 is a deficient number, since it is larger than the sum of its proper divisors (474532187).

113413135333 is an equidigital number, since it uses as much as digits as its factorization.

113413135333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 474532186.

The product of its digits is 14580, while the sum is 31.

Adding to 113413135333 its reverse (333531314311), we get a palindrome (446944449644).

The spelling of 113413135333 in words is "one hundred thirteen billion, four hundred thirteen million, one hundred thirty-five thousand, three hundred thirty-three".