Base | Representation |
---|---|
bin | 1010010100001010000011… |
… | …1011101001011101001111 |
3 | 1111011020011121200012221201 |
4 | 2211002200323221131033 |
5 | 2441304203343333203 |
6 | 40042101251010331 |
7 | 2250250542303040 |
oct | 245024073513517 |
9 | 44136147605851 |
10 | 11341413652303 |
11 | 3682959378139 |
12 | 13320605999a7 |
13 | 64364c153a67 |
14 | 2b2cda90c8c7 |
15 | 14a0399dee1d |
hex | a50a0ee974f |
11341413652303 has 4 divisors (see below), whose sum is σ = 12961615602640. Its totient is φ = 9721211701968.
The previous prime is 11341413652297. The next prime is 11341413652321. The reversal of 11341413652303 is 30325631414311.
11341413652303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11341413652303 - 229 = 11340876781391 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11341413652603) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 810100975158 + ... + 810100975171.
It is an arithmetic number, because the mean of its divisors is an integer number (3240403900660).
Almost surely, 211341413652303 is an apocalyptic number.
11341413652303 is a deficient number, since it is larger than the sum of its proper divisors (1620201950337).
11341413652303 is an equidigital number, since it uses as much as digits as its factorization.
11341413652303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1620201950336.
The product of its (nonzero) digits is 77760, while the sum is 37.
The spelling of 11341413652303 in words is "eleven trillion, three hundred forty-one billion, four hundred thirteen million, six hundred fifty-two thousand, three hundred three".
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