Base | Representation |
---|---|
bin | 11001110010011110101110… |
… | …101111111111101001100111 |
3 | 112212120212012002120002022222 |
4 | 121302132232233333221213 |
5 | 104331233413044440120 |
6 | 1041120253451542555 |
7 | 32614222430211305 |
oct | 3162365657775147 |
9 | 485525162502288 |
10 | 113420133202535 |
11 | 33159232377325 |
12 | 108796b915aa5b |
13 | 4b3961b5b4693 |
14 | 20017c6c77275 |
15 | d1a4b812d525 |
hex | 6727aebffa67 |
113420133202535 has 16 divisors (see below), whose sum is σ = 136180988138880. Its totient is φ = 90684898725120.
The previous prime is 113420133202499. The next prime is 113420133202547. The reversal of 113420133202535 is 535202331024311.
It is not a de Polignac number, because 113420133202535 - 236 = 113351413725799 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113420133202495 and 113420133202504.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 82162379 + ... + 83531411.
It is an arithmetic number, because the mean of its divisors is an integer number (8511311758680).
Almost surely, 2113420133202535 is an apocalyptic number.
113420133202535 is a deficient number, since it is larger than the sum of its proper divisors (22760854936345).
113420133202535 is a wasteful number, since it uses less digits than its factorization.
113420133202535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1378378.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 113420133202535 its reverse (535202331024311), we get a palindrome (648622464226846).
The spelling of 113420133202535 in words is "one hundred thirteen trillion, four hundred twenty billion, one hundred thirty-three million, two hundred two thousand, five hundred thirty-five".
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