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11342154034 = 25671077017
BaseRepresentation
bin10101001000000101…
…11000100100110010
31002021110021010100001
422210002320210302
5141212042412114
65113245420214
7551032501321
oct124402704462
932243233301
1011342154034
1148a0394222
12224656a66a
1310b9a94563
147984d80b8
15465b28374
hex2a40b8932

11342154034 has 4 divisors (see below), whose sum is σ = 17013231054. Its totient is φ = 5671077016.

The previous prime is 11342154017. The next prime is 11342154073. The reversal of 11342154034 is 43045124311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10835769025 + 506385009 = 104095^2 + 22503^2 .

It is a super-3 number, since 3×113421540343 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11342153993 and 11342154011.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2835538507 + ... + 2835538510.

Almost surely, 211342154034 is an apocalyptic number.

11342154034 is a deficient number, since it is larger than the sum of its proper divisors (5671077020).

11342154034 is an equidigital number, since it uses as much as digits as its factorization.

11342154034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5671077019.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 11342154034 its reverse (43045124311), we get a palindrome (54387278345).

The spelling of 11342154034 in words is "eleven billion, three hundred forty-two million, one hundred fifty-four thousand, thirty-four".

Divisors: 1 2 5671077017 11342154034