1134220133401 has 4 divisors (see below), whose sum is σ = 1136588025600. Its totient is φ = 1131852241204.

The previous prime is 1134220133399. The next prime is 1134220133461. The reversal of 1134220133401 is 1043310224311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1134220133401 - 2¹ = 1134220133399 is a prime.

It is a super-2 number, since 2×1134220133401² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1134220133461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1183945381 + ... + 1183946338.

It is an arithmetic number, because the mean of its divisors is an integer number (284147006400).

Almost surely, 2^{1134220133401} is an apocalyptic number.

It is an amenable number.

1134220133401 is a deficient number, since it is larger than the sum of its proper divisors (2367892199).

1134220133401 is an equidigital number, since it uses as much as digits as its factorization.

1134220133401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2367892198.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1134220133401 its reverse (1043310224311), we get a palindrome (2177530357712).

It can be divided in two parts, 1134220 and 133401, that added together give a palindrome (1267621).

The spelling of 1134220133401 in words is "one trillion, one hundred thirty-four billion, two hundred twenty million, one hundred thirty-three thousand, four hundred one".