Base | Representation |
---|---|
bin | 10000100000010100110… |
… | …011100111111100001111 |
3 | 11000102121202212102001122 |
4 | 100200110303213330033 |
5 | 122040340413142112 |
6 | 2225015332231155 |
7 | 144642016461062 |
oct | 20402463477417 |
9 | 4012552772048 |
10 | 1134220443407 |
11 | 3a8024964687 |
12 | 1639a016b4bb |
13 | 82c5865625c |
14 | 3cc7a24a8d9 |
15 | 1e784d96872 |
hex | 10814ce7f0f |
1134220443407 has 4 divisors (see below), whose sum is σ = 1134884120040. Its totient is φ = 1133556766776.
The previous prime is 1134220443403. The next prime is 1134220443449. The reversal of 1134220443407 is 7043440224311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1134220443407 - 22 = 1134220443403 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1134220443403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 331835753 + ... + 331839170.
It is an arithmetic number, because the mean of its divisors is an integer number (283721030010).
Almost surely, 21134220443407 is an apocalyptic number.
1134220443407 is a deficient number, since it is larger than the sum of its proper divisors (663676633).
1134220443407 is an equidigital number, since it uses as much as digits as its factorization.
1134220443407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 663676632.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 1134220443407 its reverse (7043440224311), we get a palindrome (8177660667718).
The spelling of 1134220443407 in words is "one trillion, one hundred thirty-four billion, two hundred twenty million, four hundred forty-three thousand, four hundred seven".
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