11342433433141 has 4 divisors (see below), whose sum is σ = 11342485800000. Its totient is φ = 11342381066284.

The previous prime is 11342433433117. The next prime is 11342433433189. The reversal of 11342433433141 is 14133433424311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11342433433141 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11342433433141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11342433433241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25857181 + ... + 26292178.

It is an arithmetic number, because the mean of its divisors is an integer number (2835621450000).

Almost surely, 2^{11342433433141} is an apocalyptic number.

It is an amenable number.

11342433433141 is a deficient number, since it is larger than the sum of its proper divisors (52366859).

11342433433141 is an equidigital number, since it uses as much as digits as its factorization.

11342433433141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 52366858.

The product of its digits is 124416, while the sum is 37.

Adding to 11342433433141 its reverse (14133433424311), we get a palindrome (25475866857452).

The spelling of 11342433433141 in words is "eleven trillion, three hundred forty-two billion, four hundred thirty-three million, four hundred thirty-three thousand, one hundred forty-one".