11343305131 has 16 divisors (see below), whose sum is σ = 12386234880. Its totient is φ = 10347218560.

The previous prime is 11343305069. The next prime is 11343305153. The reversal of 11343305131 is 13150334311.

It is a cyclic number.

It is not a de Polignac number, because 11343305131 - 2¹⁵ = 11343272363 is a prime.

It is a super-2 number, since 2×11343305131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11343305096 and 11343305105.

It is not an unprimeable number, because it can be changed into a prime (11343305191) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8431 + ... + 150856.

It is an arithmetic number, because the mean of its divisors is an integer number (774139680).

Almost surely, 2^11343305131 is an apocalyptic number.

11343305131 is a deficient number, since it is larger than the sum of its proper divisors (1042929749).

11343305131 is a wasteful number, since it uses less digits than its factorization.

11343305131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 159434.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 11343305131 its reverse (13150334311), we get a palindrome (24493639442).

The spelling of 11343305131 in words is "eleven billion, three hundred forty-three million, three hundred five thousand, one hundred thirty-one".