Base | Representation |
---|---|
bin | 1010010100010001001011… |
… | …0011111001011110100111 |
3 | 1111011102002202202021210011 |
4 | 2211010102303321132213 |
5 | 2441322112000122044 |
6 | 40043015021111051 |
7 | 2250346102011130 |
oct | 245042263713647 |
9 | 44142082667704 |
10 | 11343324223399 |
11 | 3683749893513 |
12 | 13324b43b8487 |
13 | 643894c190bc |
14 | 2b303c568c87 |
15 | 14a0ec5da134 |
hex | a5112cf97a7 |
11343324223399 has 16 divisors (see below), whose sum is σ = 13530932448768. Its totient is φ = 9297717450912.
The previous prime is 11343324223369. The next prime is 11343324223493. The reversal of 11343324223399 is 99332242334311.
It is a cyclic number.
It is not a de Polignac number, because 11343324223399 - 213 = 11343324215207 is a prime.
It is a super-2 number, since 2×113433242233992 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11343324223369) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8462137 + ... + 9710530.
It is an arithmetic number, because the mean of its divisors is an integer number (845683278048).
Almost surely, 211343324223399 is an apocalyptic number.
11343324223399 is a deficient number, since it is larger than the sum of its proper divisors (2187608225369).
11343324223399 is a wasteful number, since it uses less digits than its factorization.
11343324223399 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18176574.
The product of its digits is 2519424, while the sum is 49.
The spelling of 11343324223399 in words is "eleven trillion, three hundred forty-three billion, three hundred twenty-four million, two hundred twenty-three thousand, three hundred ninety-nine".
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