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113433554401 = 1283208942323
BaseRepresentation
bin110100110100100101…
…0101010110111100001
3101211210101020121112121
41221221022222313201
53324302442220101
6124035522424241
711123663206066
oct1515112526741
9354711217477
10113433554401
114411a314382
1219b98802081
13a9099707bb
1456c1206c6d
152e3d77c0a1
hex1a692aade1

113433554401 has 8 divisors (see below), whose sum is σ = 113578993440. Its totient is φ = 113288206752.

The previous prime is 113433554393. The next prime is 113433554467. The reversal of 113433554401 is 104455334311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113433554401 - 23 = 113433554393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113433554471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2659026 + ... + 2701348.

It is an arithmetic number, because the mean of its divisors is an integer number (14197374180).

Almost surely, 2113433554401 is an apocalyptic number.

It is an amenable number.

113433554401 is a deficient number, since it is larger than the sum of its proper divisors (145439039).

113433554401 is a wasteful number, since it uses less digits than its factorization.

113433554401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45695.

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 113433554401 its reverse (104455334311), we get a palindrome (217888888712).

The spelling of 113433554401 in words is "one hundred thirteen billion, four hundred thirty-three million, five hundred fifty-four thousand, four hundred one".

Divisors: 1 1283 2089 42323 2680187 54300409 88412747 113433554401