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11343370073 = 71620481439
BaseRepresentation
bin10101001000001111…
…00001011101011001
31002021112112220102112
422210013201131121
5141212400320243
65113331442105
7551046024530
oct124407413531
932245486375
1011343370073
1148a1044912
122246a56335
1310ba0cbbc9
14798733317
15465cb8818
hex2a41e1759

11343370073 has 4 divisors (see below), whose sum is σ = 12963851520. Its totient is φ = 9722888628.

The previous prime is 11343370061. The next prime is 11343370091. The reversal of 11343370073 is 37007334311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11343370073 - 216 = 11343304537 is a prime.

It is a super-2 number, since 2×113433700732 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11343370033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 810240713 + ... + 810240726.

It is an arithmetic number, because the mean of its divisors is an integer number (3240962880).

Almost surely, 211343370073 is an apocalyptic number.

It is an amenable number.

11343370073 is a deficient number, since it is larger than the sum of its proper divisors (1620481447).

11343370073 is an equidigital number, since it uses as much as digits as its factorization.

11343370073 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1620481446.

The product of its (nonzero) digits is 15876, while the sum is 32.

The spelling of 11343370073 in words is "eleven billion, three hundred forty-three million, three hundred seventy thousand, seventy-three".

Divisors: 1 7 1620481439 11343370073