11343431413 has 4 divisors (see below), whose sum is σ = 11411356320. Its totient is φ = 11275506508.

The previous prime is 11343431321. The next prime is 11343431417. The reversal of 11343431413 is 31413434311.

11343431413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11343431413 - 2¹⁷ = 11343300341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11343431417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33962203 + ... + 33962536.

It is an arithmetic number, because the mean of its divisors is an integer number (2852839080).

Almost surely, 2^11343431413 is an apocalyptic number.

It is an amenable number.

11343431413 is a deficient number, since it is larger than the sum of its proper divisors (67924907).

11343431413 is an equidigital number, since it uses as much as digits as its factorization.

11343431413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67924906.

The product of its digits is 5184, while the sum is 28.

Adding to 11343431413 its reverse (31413434311), we get a palindrome (42756865724).

The spelling of 11343431413 in words is "eleven billion, three hundred forty-three million, four hundred thirty-one thousand, four hundred thirteen".