Base | Representation |
---|---|
bin | 11001110010101100111101… |
… | …011111110101011111100001 |
3 | 112212122022121222012202020211 |
4 | 121302230331133311133201 |
5 | 104332011211212313101 |
6 | 1041131302003134121 |
7 | 32615303165351146 |
oct | 3162547537653741 |
9 | 485568558182224 |
10 | 113435413010401 |
11 | 33164763431109 |
12 | 10880662374341 |
13 | 4b3abb50ab801 |
14 | 20024362d63cd |
15 | d1aaae7b3c51 |
hex | 672b3d7f57e1 |
113435413010401 has 16 divisors (see below), whose sum is σ = 125220188041344. Its totient is φ = 102312342123264.
The previous prime is 113435413010389. The next prime is 113435413010443. The reversal of 113435413010401 is 104010314534311.
It is a cyclic number.
It is not a de Polignac number, because 113435413010401 - 25 = 113435413010369 is a prime.
It is a super-2 number, since 2×1134354130104012 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113435417010401) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1463908461 + ... + 1463985946.
It is an arithmetic number, because the mean of its divisors is an integer number (7826261752584).
Almost surely, 2113435413010401 is an apocalyptic number.
It is an amenable number.
113435413010401 is a deficient number, since it is larger than the sum of its proper divisors (11784775030943).
113435413010401 is a wasteful number, since it uses less digits than its factorization.
113435413010401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2927894520.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 113435413010401 its reverse (104010314534311), we get a palindrome (217445727544712).
The spelling of 113435413010401 in words is "one hundred thirteen trillion, four hundred thirty-five billion, four hundred thirteen million, ten thousand, four hundred one".
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