Base | Representation |
---|---|
bin | 10101001000010000… |
… | …11111101110111011 |
3 | 1002021120000212022201 |
4 | 22210020133232323 |
5 | 141212432001042 |
6 | 5113341131031 |
7 | 551051136301 |
oct | 124410375673 |
9 | 32246025281 |
10 | 11343625147 |
11 | 48a11a9518 |
12 | 2246b59a77 |
13 | 10ba18b03a |
14 | 79879c271 |
15 | 465d191b7 |
hex | 2a421fbbb |
11343625147 has 4 divisors (see below), whose sum is σ = 11535890040. Its totient is φ = 11151360256.
The previous prime is 11343625127. The next prime is 11343625151. The reversal of 11343625147 is 74152634311.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 74152634311 = 7 ⋅10593233473.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11343625147 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11343625127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96132358 + ... + 96132475.
It is an arithmetic number, because the mean of its divisors is an integer number (2883972510).
Almost surely, 211343625147 is an apocalyptic number.
11343625147 is a deficient number, since it is larger than the sum of its proper divisors (192264893).
11343625147 is an equidigital number, since it uses as much as digits as its factorization.
11343625147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 192264892.
The product of its digits is 60480, while the sum is 37.
The spelling of 11343625147 in words is "eleven billion, three hundred forty-three million, six hundred twenty-five thousand, one hundred forty-seven".
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