Base | Representation |
---|---|
bin | 10000100000011111100… |
… | …100110111011101110011 |
3 | 11000110002100211221112021 |
4 | 100200133210313131303 |
5 | 122041223141433321 |
6 | 2225045305012311 |
7 | 144646342313215 |
oct | 20403744673563 |
9 | 4013070757467 |
10 | 1134401124211 |
11 | 3a8107951863 |
12 | 163a30784097 |
13 | 82c86c07c84 |
14 | 3cc962405b5 |
15 | 1e795b86941 |
hex | 1081f937773 |
1134401124211 has 4 divisors (see below), whose sum is σ = 1139488124992. Its totient is φ = 1129314123432.
The previous prime is 1134401124187. The next prime is 1134401124217. The reversal of 1134401124211 is 1124211044311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1134401124211 - 27 = 1134401124083 is a prime.
It is a super-2 number, since 2×11344011242112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1134401124217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2543500056 + ... + 2543500501.
It is an arithmetic number, because the mean of its divisors is an integer number (284872031248).
Almost surely, 21134401124211 is an apocalyptic number.
1134401124211 is a deficient number, since it is larger than the sum of its proper divisors (5087000781).
1134401124211 is an equidigital number, since it uses as much as digits as its factorization.
1134401124211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5087000780.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 1134401124211 its reverse (1124211044311), we get a palindrome (2258612168522).
The spelling of 1134401124211 in words is "one trillion, one hundred thirty-four billion, four hundred one million, one hundred twenty-four thousand, two hundred eleven".
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